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-5x^2-35x-60=0
a = -5; b = -35; c = -60;
Δ = b2-4ac
Δ = -352-4·(-5)·(-60)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-5}{2*-5}=\frac{30}{-10} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+5}{2*-5}=\frac{40}{-10} =-4 $
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